SOLUTION: Divide 2x^3+3x^2-50x+75 by (2x+3) and hence solve for x if 2x^3+3x^2-50x+75=0

Question 1148177: Divide 2x^3+3x^2-50x+75 by (2x+3) and hence solve for x if 2x^3+3x^2-50x+75=0
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52847) (Show Source): You can put this solution on YOUR website!
.

Go boldly forward and divide it on your own.

~~~~~~~~~~~~~~~~~

Why tutors should do this mechanical primitive job for you or instead of you ?

Making calculations is the student' honor duty and a privilege !

Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!
Format to begin:

----------------------------------- 2x+3 | 2x^3 + 3x^2 -50x + 75 | |

First step:
What is 2x^3/2x?
x^2.

x^2 ----------------------------------- 2x+3 | 2x^3 + 3x^2 -50x + 75 | |

Do what would normally be done in "regular" long division. You continue.
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