SOLUTION: find the horizontal and verticle asymptotes for the function g(x)=2x^2/3x^2-1

Question 114303: find the horizontal and verticle asymptotes for the function
g(x)=2x^2/3x^2-1

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the horizontal and verticle asymptotes for the function
g(x)=2x^2/3x^2-1
-------------------
Vertical asymptotes occur where the denominator is zero:
3x^2-1 = 0
x^2 = 1/3
x = [sqrt3]/3 or x= [-sqrt3]/3
--------------------
horizontal asymptote:
y = 2x^2/3x^2 = 2/3
=========================
Cheers,
Stan H.
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