SOLUTION: Please explain how to find real solutions and check for extraneous solutions:
1/(w+3) + 1/(w-3)= (w^2-3)/(w^2-9)
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Question 1139129: Please explain how to find real solutions and check for extraneous solutions:
1/(w+3) + 1/(w-3)= (w^2-3)/(w^2-9)
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
since denominator cannot be equal to zero, solution that makes
=> and =>extraneous solutions
real solution will be that makes numerators equal
solutions:
=>this solution is already excluded
or
=> this is your solution
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