SOLUTION: I tried dividing by nine on both sides and it got me to 4x^2 - 2x - 13/2 = 0. But I don't know what to do next. Find the dimensions: *triangle* base of (2x+1) and height of (2x-

SOLUTION: I tried dividing by nine on both sides and it got me to 4x^2 - 2x - 13/2 = 0. But I don't know what to do next. Find the dimensions: triangle base of (2x+1) and height of (2x-

Question 1135155: I tried dividing by nine on both sides and it got me to 4x^2 - 2x - 13/2 = 0. But I don't know what to do next.
Find the dimensions: *triangle* base of (2x+1) and height of (2x-2)
Please help.
Thanks in advance.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39621) (Show Source): You can put this solution on YOUR website!
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I tried dividing by nine on both sides and it got me to 4x^2 - 2x - 13/2 = 0. But I don't know what to do next.
Find the dimensions: *triangle* base of (2x+1) and height of (2x-2)
Please help.
Thanks in advance.
-----

Why the 9? Where did that come from? Was 9 the value for the area?

If area is 9, then

Can you finish from here? Either try factorizing or use general solution of quadratic equation.
Answer by ikleyn(52817) (Show Source): You can put this solution on YOUR website!
.

In a way on how the problem is formulated in your post, it can not be solved.

If you want to get a solution and a help, print the problem formulation "word-in-word" from your source.

It is the only way to stay on solid ground.

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