SOLUTION: The rectangular floor of a closet is divided into two right triangles by drawing a diagonal. One leg of the right triangle is 10 feet less than twice than twice the other leg. The

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Question 1134641: The rectangular floor of a closet is divided into two right triangles by drawing a diagonal. One leg of the right triangle is 10 feet less than twice than twice the other leg. The hypotenuse is 25 feet. Determine the​ closet's length and width. Let the width be the shorter side.
Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52792)   (Show Source): You can put this solution on YOUR website!
.
Let w be the width.  Then the length is  (2w - 10).


Your equation to find "w" is


w^2 + (2w-10)^2 = 25^2.


Simplify and solve for w.


Then evaluate 2w-10 as the length.


Happy calculations !


Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

The rectangular floor of a closet is divided into two right triangles by drawing a diagonal.
One leg of the right triangle is feet less than twice the other leg.



Let be the width. Then the length is .
Your equation to find "" is


.....simplify


...factor


-> disregard negative solution


find the other leg = :

the​ closet's length is ft and width is ft


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