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Let a, b and c be these roots.
Since they form an AP, we can write them as m-d, m and m+d, where m is the middle term m=b and d is the common difference, so
a = m-d, c = m+d.
Then according to the Vieta's theorem, the sum of the roots is equal to the coefficient at taken with the opposite sign:
(m-d) + m + (m+d) = 9, or 3m = 9, which implies m = 9/3 = 3.
The product of the roots, using the Vieta's theorem again, is equal to the constant term taken with the opposite sign:
(3-d)*3*(3+d) = 15, or = 15/3 = 5, which implies = 9 - 5 = 4; hence, d = +/- = +/-2.
In this way, the AP is EITHER 3-2 = 1, 3, 3+2 = 5 OR 5, 3, 1, which makes no difference.
Answer. The roots are 1, 3 and 5.
Solved.