SOLUTION: How many complex, real, and rational roots does the following polynomial have: 2x^5-4x^4-4x^2+5 I think the number of complex roots would be 5, and the number of rational roots

Question 1131290: How many complex, real, and rational roots does the following polynomial have:
2x^5-4x^4-4x^2+5
I think the number of complex roots would be 5, and the number of rational roots would be 4, but am confused about how to find the number of real roots.
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

given:
->It is degree , so there are roots.
we can say how many are or just by counting how many times the sign changes (from plus to minus, or minus to plus)
The number of sign changes is the maximum number of positive roots.
you have:
-> sign +
-> sign - which is
-> sign - no change
-> sign + which is
There are changes in sign, so there are at most roots (maybe less).So there could be , or , or positive roots.
By doing a similar calculation we can find out how many roots are " in place of "", like this:

=
Only the odd exponents, like ,,, etc will reverse their sign:
only have changed to
One change only, so there is negative root.
So there are at most positive roots and negative root, there are at most real roots.

we also know Complex Roots always come in pairs which means we either get:
complex roots
complex roots
complex roots,
etc
in this case we will have complex roots because we have at most real roots

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