SOLUTION: State method and factor completely 2p-6q+pq-3q^ The method to be used is the grouping of terms but I am stuck on the factoring part because the 3q^ is not factorable if I'm not

Question 113019: State method and factor completely
2p-6q+pq-3q^
The method to be used is the grouping of terms but I am stuck on the factoring part because the 3q^ is not factorable if I'm not mistaken. Can you assist me on understanding this problem.
Found 2 solutions by jim_thompson5910, SHUgrad05:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given expression

Group like terms

Factor out the GCF of out of the first group. Factor out the GCF of out of the second group

Since we have a common term of , we can combine like terms

So factors to
Answer by SHUgrad05(58) (Show Source): You can put this solution on YOUR website!
Should the problem read: 2p-6q+pq-3q^2???
If so, group the first two terms and the last two terms then factor:
(2p-6q)+(pq-3q^2)
2(p-3q)+q(p-3q)
(2+q)(p-3q)