SOLUTION: Perform the operation. Simplify your answer, if possible. Assume that no denominators are 0.
x / (x-2) + (4+2x) / (x^2-4)
Algebra.Com
Question 1128979: Perform the operation. Simplify your answer, if possible. Assume that no denominators are 0.
x / (x-2) + (4+2x) / (x^2-4)
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
---
x / (x-2) + (4+2x) / (x^2-4)
---
The first step is:
A couple of combined simplifications steps could be
...
and then few more steps...
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
so the common denominator is .
Multiply numerator and denominator of the first fraction by (x+2); combine into a single fraction with the common denominator; and simplify the numerator by combining like terms. Then look to see if the numerator can be factored; possibly the numerator and denominator will have a common factor that allows further simplification.
RELATED QUESTIONS
Perform the operation. Simplify your answer, if possible. Assume that no denominators are (answered by josgarithmetic)
Perform the operation. Assume that no denominators are 0. (Simplify your answer... (answered by Alan3354)
Perform the indicated operation. Assume that no denominators are 0. Simplify your answer... (answered by MathLover1)
Perform the operations. Assume that no denominators are 0. Simplify your answer if... (answered by MathLover1)
Perform the operation. Assume that no denominators are 0. Simplify your answer if... (answered by MathLover1)
Perform the operation. Assume that no denominators are 0. (Simplify your answer... (answered by Boreal)
Perform the indicated operation. Assume that no denominators are 0. Simplify your answer... (answered by MathLover1)
Perform the operations. Simplify your answer, if possible. Assume that no denominators... (answered by MathLover1)
Perform the indicated operation. Assume that no denominators are 0. Simplify your answer... (answered by MathLover1,MathTherapy)