SOLUTION: What are the zeros of the polynomial function?
{{{ f(x) = x^4 - 4x^3 - 22x^2 + 4x + 21 }}}
Select EACH correct answer.
A. -3
B. -1
C. 0
D. 1
E. 3
F. 7
Algebra.Com
Question 1127716: What are the zeros of the polynomial function?
Select EACH correct answer.
A. -3
B. -1
C. 0
D. 1
E. 3
F. 7
Found 2 solutions by greenestamps, josgarithmetic:
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
0 can't be a root; if it were, the constant term would be 0.
Test 1 and -1 by evaluating the polynomial at those values. It turns out f(1)=0 and f(-1)=0, so both are roots. Roots of 1 and -1 correspond to binomial factors of x-1 and x+1; factor them out by factoring, long division, synthetic division, or any other method you know.
x^4-4x^3-22x^2+4x+21 = (x-1)(x+1)(x^2-4x-21)
The remaining quadratic is easily factored:
x^4-4x^3-22x^2+4x+21 = (x-1)(x+1)(x-7)(x+3)
The roots are 1, -1, -3, and 7.
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
-----
What are the zeros of the polynomial function?
Select EACH correct answer.
-------
Four of them easily found using synthetic division to check:
A, B, D, F.
A. -3
B. -1
C. 0
D. 1
E. 3
F. 7
...
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