Find a polynomial of the specified degree that satisfies the given conditions.
Degree 5; zeros -3, -1, 3 and
square of 3
; integer coefficients and constant term 54
The zeros are:
Multiply left and right sides:
Multiply both sides by a constant A:
FOIL out the last two parentheses on the left:
FOIL out the last two parentheses on the left again:
Get the last parentheses in descending order:
Multiply the last two factors in parentheses on the left:
Distribute the A:
Since the constant term 27A must equal 54, we set
them equal:
27A = 54
A = 2
So
becomes
or
So the polynomial is the left side without the "= 0".
Edwin