SOLUTION: I have three zeros 3-3i,3+3i, and 3. I am having trouble factoring. I am missing something in the factoring that will get me the right equation. This is what I have so far (x-(3-3i

Question 1123854: I have three zeros 3-3i,3+3i, and 3. I am having trouble factoring. I am missing something in the factoring that will get me the right equation. This is what I have so far (x-(3-3i))(x-(3+3i))(x-3). (x-(3-3i))(3+3i)) should factor out to x^2-6x+10 I keep getting x^2-2x+18. The final equation should be x^3-9x^2+28x-30. Could you please assist me with this by working out the factoring to see where I am going wrong.
Thanks
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

zeros:,, and
to find equation, use product of factors
...substitute given zeros

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