Factor x³ + (x+3)³ Let y = x+3, then the above becomes: x³ + y³ By the method for factoring the sum of two cubes, the above becomes: (x + y)(x² - xy + y²) Change the parentheses to brackets [x + y][x² - xy + y²] Replace the y's by (x+3) [x + (x+3)][x² - x(x+3) + (x+3)²] [x + x + 3][x² - x² - 3x + (x+3)(x+3)] [2x + 3][-3x + (x²+3x+3x+9)] [2x + 3][-3x + (x²+6x+9)] [2x + 3][-3x + x² + 6x + 9] [2x + 3][x² + 3x + 9] Change the brackets to parentheses: (2x + 3)(x² + 3x + 9) Edwin