SOLUTION: Problem Page The area of a rectangle is 65ft^2 and the length of the rectangle is 3ft less than twice the width. Find the dimensions of the rectangle.
W*L = 65
W*(2W-3) = 65
2W^ - 3W - 65 = 0
= = .
Answer. The width is W = = 6.5ft.
The length is L = 2W - 3 = 10 ft.
Check. 10*6.5 = 65. ! Correct !
Solved.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website! Problem Page The area of a rectangle is 65ft^2 and the length of the rectangle is 3ft less than twice the width. Find the dimensions of the rectangle.
Width = W
Length = 2W-3
-----
Equation:
W(2W-3) = 65
-----
2W^2 - 3W - 65 = 0
W = [3+-sqrt(9-4*2*-65)]/4
W = [3+-sqrt(529)]/4
positive solution:
W = 6.5 ft (width)
2W-3 = 10 ft (length)
------
Cheers,
Stan H.
----------------------