SOLUTION: Two cars race on a 4 mile oval track. The sum of their rates is 200 miles per hour. Find the rate of each if the faster car gains one lap in 40 minutes. My work: I know the

Question 1111915: Two cars race on a 4 mile oval track. The sum of their rates is 200 miles per hour. Find the rate of each if the faster car gains one lap in 40 minutes.

My work:
I know the rate of the slower car is 200-x and the rate of the other car is x. Then I know the time of slower car is 4/(200-x) and the time of the other car is 4/x. The distance for both is 4 miles. I'm not sure what to do with the "faster car gains one lap in 40 minutes". Thank you for your help!
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Two cars race on a 4 mile oval track.
The sum of their rates is 200 miles per hour.
Find the rate of each if the faster car gains one lap in 40 minutes.
Let a = the faster car rate
:
In 40 min car a is 4 mi ahead of slower car
therefore, in one hr it will be 6 mi ahead.
Car a is 6 mph faster than the slower car
a + (a-6) = 200
2a = 206
a = 103 mph, slower car = 97 mph
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