SOLUTION: A rectangle is twice as long as it is wide. If both of its dimensions are increased by 4 m, its area is increased by 88 m^2. Find the dimensions of the original rectangle.
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Question 1111013: A rectangle is twice as long as it is wide. If both of its dimensions are increased by 4 m, its area is increased by 88 m^2. Find the dimensions of the original rectangle.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let width be x
length will be 2 x
Area of rectangle = 2x^2
both dimensions are increased by 4
width = x + 4
length = 2 x + 4
As per the condition
(x+ 4 )*( 2 x+ 4 )= 2 x^2+ 88 )
2 x^2+ 4 x+ 8 x 16 = 2 x^2+ 88
Simplify
12 x= 72
x= 6
width = 6 m
length= 12 m
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