SOLUTION: The polynomial of degree 5, P(x), has leading coefficient 1, has roots of multiplicity 2 at x=2 and x=0, and a root of multiplicity 1 at x=−3.
Find a possible formula for
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Question 1110665: The polynomial of degree 5, P(x), has leading coefficient 1, has roots of multiplicity 2 at x=2 and x=0, and a root of multiplicity 1 at x=−3.
Find a possible formula for P(x).
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
If has a root of multiplicity 1 at ,
there must be a factor in its factored form.
If a polynomial has a root with multiplicity 2,
must appear in that polynomial's factored form,
so
is an expression for the polynomial in this problem.
It is a polynomial of degree 5, and its leading coefficient is 1.
For another form, we multiply
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