SOLUTION: Hi this is a word problem: Suppose z varies directly as x and inversely as the square of y. if z = 1/4 when x = 6 and y = 8, find z when x = 9 and y = 2.
This is something tha
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Question 110874This question is from textbook College Algebra
: Hi this is a word problem: Suppose z varies directly as x and inversely as the square of y. if z = 1/4 when x = 6 and y = 8, find z when x = 9 and y = 2.
This is something that I have attempted and I know I am way off:
1/4 = (k)6/8^2 k/64 1/4 = k/64 16 = k
z = (16(9)/2^2 144/4 = 36
Yeah way off base!!!
Thanks
This question is from textbook College Algebra
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
z = 1/4 when x = 6 and y = 8. Find k[1]and k[2]
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Find z when x = 9 and y = 2
answer
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z = 3/8 when x = 9, and z = 4 when y = 2
unless I goofed
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