SOLUTION: x+y+z =0 then find the value of (x+y)(y+z)(x+z)/xyz +11

Algebra.Com
Question 1107842: x+y+z =0 then find the value of (x+y)(y+z)(x+z)/xyz +11
Answer by math_helper(2461)   (Show Source): You can put this solution on YOUR website!
x+y+z =0 then find the value of (x+y)(y+z)(x+z)/xyz +11
============================================
ans: 10
( x,y, and z each nonzero )
———————————————
x+y+z=0 —> -x = y+z, -y = x+z, -z = x+y
So
(x+y)(y+z)(x+z)/xyz +11
can be re-written:
(-z)(-x)(-y)/(xyz) + 11 = -1 + 11 = 10, so long as x,y,and z are each nonzero.

RELATED QUESTIONS

if a=b^x, b=c^y, c=a^z then find the value of... (answered by ramkikk66)
Solve xyz=x + y + z for... (answered by stanbon)
Suppose x,y,z >0. Prove that {{{x^3 + y^3 >= xyz(x/z +... (answered by Edwin McCravy)
If x+y+z=16 then find the maximum value of (x-3)(y-5)(z-2). Given that (x-3)>0,... (answered by Edwin McCravy,ikleyn)
x(y+z)=6 y(z+x)=10 z(x+y)=12 find the value of... (answered by Edwin McCravy)
x+y+z=23 xyz=396 x=? y=?... (answered by Fombitz)
X+Y+Z=4, X+Y-Z=4, 3X+3Y+Z=12 FIND VARIABLE... (answered by greenestamps)
If for three distinct positive numbers x, y, and z, {{{ y/(x-z) = (x+y)/z = x/y }}}... (answered by ikleyn)
The value of xyz is 15/2 if a, x, y, z, b in AP. While xyz is 18/5 if a, x, y, z, b in... (answered by Edwin McCravy)