SOLUTION: Subtracting the product of (3x-1) and (2x^2-4x+3) from the sum of (2x^3-7x^2-6) and (x^2+6x-3) results in a polynomial of the form (ax^3+bx^2+cx+d). What is the value of b-2c?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Subtracting the product of (3x-1) and (2x^2-4x+3) from the sum of (2x^3-7x^2-6) and (x^2+6x-3) results in a polynomial of the form (ax^3+bx^2+cx+d). What is the value of b-2c?      Log On


   

Question 1106675: Subtracting the product of (3x-1) and (2x^2-4x+3) from the sum of
(2x^3-7x^2-6) and (x^2+6x-3) results in a polynomial of the form (ax^3+bx^2+cx+d). What is the value of b-2c?
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
Setup the expression according to the worded description and do the arithmetic.

%282x%5E3-7x%5E2-6%29%2B%28x%5E2%2B6x-3%29-%283x-1%29%282x%5E2-4x%2B3%29
.
.
-4x%5E3%2B8x%5E2-7x-6=ax%5E3%2Bbx%5E2%2Bcx%2Bd%29

Find b-2c.
8-2%28-7%29
8%2B14
highlight_green%2822%29