SOLUTION: find the zeros of the polynomial by prime factorisation method 2x^2 + 7/2x + 3/4

Question 1105874: find the zeros of the polynomial by prime factorisation method 2x^2 + 7/2x + 3/4
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
Multiply everything by 4 to clear fractions
8x^2+14x+3=0
guess and check is (4x+1)(2x+3)=0, and zeros are -1/4 and -3/2
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also
grouping 8x^2+2x+12x+3=2(4x+1)+3(4x+1)
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also convert equation to
x^2+14x+24, dividing first term by 8 and multiplying constant by 8
factor to (x+12)(x+2)
divide constant by 8 and reduce to lowest terms (x+(3/2))(x+(1/4))
put the denominator in front (2x+3)(4x+1)

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