SOLUTION: FACTOR 6(p-5)^2+11(p-5)+3

Question 1097368: FACTOR
6(p-5)^2+11(p-5)+3
Found 2 solutions by Boreal, josgarithmetic:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
let u=p-5
This is now 6u^2+11u+3
=(3u+1)(2u+3),
which is (3(p-5)+1)(2(p-5)+3)
(3p-14)(2p-7)
Check
The last is 6p^2-49p+98
The original is 6p^2-60p+150+11p-52
That is 6p^2-49p+98
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
If you let u=p-5 and then express the given expression as 6u^2+11u+3, then can you factorize this?
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