SOLUTION: If the remainder when x^3-ax^2-5x+4 is divided by (x-3) is 97 what is the value of a

Question 1095572: If the remainder when x^3-ax^2-5x+4 is divided by (x-3) is 97 what is the value of a
Answer by ikleyn(52803) (Show Source): You can put this solution on YOUR website!
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Apply the remainder theorem:


      The remainder of dividing  of a polynomial  P(x) (ANY POLYNOMIAL !!) by the binomial (x-a) is equal 
       to the value P(a) of the polynomial at x= a.


And you will get for your case

      3^3 - a*3^2 - 5*3 + 4 = 97.    (1)


It is your equation to determine the value of "a".

Now you can complete the assignment on your own, by finding "a" from the equation (1).

-------------
On the Remainder theorem, see my lessons in this site

    - Divisibility of polynomial f(x) by a binomial (x-a) and the Remainder theorem
    - Solved problems on the Remainder thoerem

Also, you have this free of charge online textbook in ALGEBRA-II in this site
    ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic
"Divisibility of polynomial f(x) by binomial (x-a). The Remainder theorem".

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