SOLUTION: Determine the values of b so that when f(x) is divided by (x-2) the remainder is -2: 1. f(x)= x^3-bx^2+4x-20 2. f(x)= -2x^4+40x^2-24x+b 3. f(x)= x^3-2bx^2+3x-4

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Question 1092470: Determine the values of b so that when f(x) is divided by (x-2) the remainder is -2:
1. f(x)= x^3-bx^2+4x-20
2. f(x)= -2x^4+40x^2-24x+b
3. f(x)= x^3-2bx^2+3x-4

Found 2 solutions by Edwin McCravy, ikleyn:
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
I'll just do the first one:
2 | 1   -b      4   -20
  |      2   4-2b   16-4b 
    1   2-b  8-2b   -4-4b

The remainder is -4-4b and it must equal to -2,
so we set the remainder equal to -2:

                -4-4b = -2
                +4      +4
                ----------
                  -4b = 2

                  
                    b = 

Edwin


Answer by ikleyn(52855)   (Show Source): You can put this solution on YOUR website!
.
Apply the Remainder theorem.


The remainder theorem says that  


    if a polynomial f(x) is divided by a binomial (x-a), where "a" is a constant term (a number), 
    then the remainder is equal to the value of f(x) at x= a, i.e. f(a).


In your case  a = 2.  By y substituting x= 2 into f(x) you get

    f(2) = 2^3 -b*2^2 + 4*2 - 20 = 8 - 4b + 8 - 20 = -4b - 4.


Therefore, your equation to find "b" is

    -4b - 4 = -2    (since -2 is the remainder !)

which implies  4b = 2 - 4 = -2,   b =  = -0.5.

Answer. b = -0.5.

Solved.

            Do the other cases in the same way.


----------------
On the Remainder theorem see the lessons
    - Divisibility of polynomial f(x) by binomial x-a
    - Solved problems on the Remainder thoerem
in this site.


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic
"Divisibility of polynomial f(x) by binomial (x-a). The Remainder theorem".


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