SOLUTION: Please help me with this problem: x+4 over x^2-3x+2 minus 5 over x^2-4x+3 = x-4 over x^2-5x+6 I know factoring comes into play but I'm lost. Please show me all of your ste

Question 109173This question is from textbook
: Please help me with this problem:
x+4 over x^2-3x+2 minus 5 over x^2-4x+3 = x-4 over x^2-5x+6
I know factoring comes into play but I'm lost.
Please show me all of your steps so I can understand what I'm doing.
Thank you This question is from textbook

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
[(x+4)/(x^2-3x+2)] - [ 5 /( x^2-4x+3)] = [(x-4)/(x^2-5x+6)]
Factor where you can to get:

[(x+4)/(x-2)(x-1))] - [ 5 /( x-1)(x-3))] = [(x-4)/(x-6)(x+1)]
Multiply thru by (x-2)(x-1)(x-3)(x-6)(x+1) to get a mess:
[(x+4)(x-3)(x-6)(x+1)] -[5(x-2)(x-6)(x+1)] = (x-4)(x-2)(x-1)(x_3)
I'll let you multiply out this mess and simplify each term.
Personally, I think this kind of problem is nothing but busy
work.
=============
Cheers,
Stan H.
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