SOLUTION: Please can you help me with this equation? 3y^2-12 /4y^2+4y+4 divided by y^3-2y^2/ Y^2+2y

Question 108821: Please can you help me with this equation?
3y^2-12 /4y^2+4y+4 divided by y^3-2y^2/ Y^2+2y

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
[(3y^2-12) /(4y^2+4y+4)] / [(y^3-2y^2) / (Y^2+2y)]
Factor where you can:
= [3y(y-4) / 4(y^2+y+1)] / [y^2(y-2) / y(y+2)]
Cancel any factor common to a numerator and a denominator such as "y":
= [3y(y-4) / 4(y^2+y+1)] / [y(y-2) / (y+2)]
Invert the denominator and multiply:
= [3y(y-4) / 4(y^2+y+1)] * [(y+2)/ y(y-2) ]
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Cancel any factor common to a numerator and a denominator such as "y":
--------------
= [3(y-4)(y+2)] / [4(y^2+y+1)(y-2)]
======================
Cheers,
Stan H.
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