SOLUTION: An astronaut on Mars throws a ball into the air with an initial velocity of 30 feet per second from a platform 36 feet tall. Gravity on Mars is approximately -12 feet per second

Algebra.Com
Question 1087358: An astronaut on Mars throws a ball into the air with an initial velocity of 30 feet per second from a platform 36 feet tall. Gravity on Mars is approximately -12 feet per second per second (-12). So, the height h of the ball t seconds after it is thrown is given by h6t2 30t 36. (a) How high is the ball after 3 seconds?
Found 2 solutions by ikleyn, jorel1380:
Answer by ikleyn(52794)   (Show Source): You can put this solution on YOUR website!
.
1.  The Mars atmosphere can hardly be called "the air".

    See this description of the Mars atmosphere from https://www.space.com/16903-mars-atmosphere-climate-weather.html :


        "The atmosphere of Mars is about 100 times thinner than Earth's, and it is 95 percent carbon dioxide. Here's a breakdown of its composition:

        Carbon dioxide: 95.32 percent
        Nitrogen: 2.7 percent
        Argon: 1.6 percent
        Oxygen: 0.13 percent
        Carbon monoxide: 0.08 percent
        Also, minor amounts of: water, nitrogen oxide, neon, hydrogen-deuterium-oxygen, krypton and xenon."



2.  The condition does not say if the ball was thrown vertically up or down, or either other way.

    The equation given also does not shed light on this subject.


3.  In the future, do not write equations without using signs. Please. Thanks.



4.  Still, if your equation is 

    h(t) = -6*t^2 + 30t + 36,   (which means that the ball was thrown vertically up)

    then, to answer your question, simply substitute t= 3 into the right side and calculate h(t).



Answer by jorel1380(3719)   (Show Source): You can put this solution on YOUR website!
If the gravity on Mars is equal to -12 ft./s², then the formula for a projectile, launched from a platform 36 ft. high, with a velocity of 30 ft./sec., would be:
h(t)=-12/2 t²+30t+36
After 3 seconds, you have:
h(3)=-6(9)+90+36=72 ft.
The ball will return to Mars at:
0=-6t²+30t+36
6t²-30t-36=0
t²-5t-6=0
(t-6)(t+1)=0
t=6 seconds before the ball hits the Martian surface.
☺☺☺☺
RELATED QUESTIONS

AN Astronaut standing on the surface of the moon throws a rock into the air with and... (answered by ankor@dixie-net.com)
Use the verticle height formula to solve the following h= -16t^ + intitial velocity +... (answered by ankor@dixie-net.com)
An astronaut on the moon throws a baseball upward. The astronaut is 6ft, 6 in. tall and... (answered by josmiceli,ankor@dixie-net.com,nerdybill)
A ball is thrown into the air with an initial velocity of 64 feet per second from a... (answered by ankor@dixie-net.com,ikleyn)
Solve rounding the answers to the nearest hundredth. 1. A javelin thrower releases a... (answered by ikleyn)
An astronaut on the moon throws a baseball upward. The astronaut is 6 fee, 6 inches tall... (answered by ikleyn)
A softball player throws a ball into the air at an initial velocity of 44 feet per... (answered by Alan3354)
An astronaut on the moon throws a baseball upward. The astronaut is 6​ ft, 6 in.​... (answered by ikleyn,Alan3354)
An astronaut on the moon throws a baseball upward. The astronaut is 6ft, 6 in tall, and... (answered by josmiceli)