SOLUTION: what is the indicated product or this 1- 2s(s-4) 2- (w+7)(w+3) 3- (x+9)(x-2) 4- (2t-1)(t+5) 5- (x+4)(x+4) 6- (2r-5)(2r-5) 7- (2h+7)(2h-7) 10- (8-3x)(8+3x) then the ans

Question 1084352: what is the indicated product or this
1- 2s(s-4)
2- (w+7)(w+3)
3- (x+9)(x-2)
4- (2t-1)(t+5)
5- (x+4)(x+4)
6- (2r-5)(2r-5)
7- (2h+7)(2h-7)
10- (8-3x)(8+3x)
then the answer and how to solved also please
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
what is the indicated product or this
1- 2s(s-4)
2- (w+7)(w+3)
3- (x+9)(x-2)
4- (2t-1)(t+5)
5- (x+4)(x+4)
6- (2r-5)(2r-5)
7- (2h+7)(2h-7)
10- (8-3x)(8+3x)
then the answer and how to solved also please
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What have you tried so far? Its also helpful when students show their work so us tutors will know the student is trying (and at least for me it makes me feel more motivated to help).
1. 2s(s-4) �> just use the distributive property to distribute (multiply through) the "2s" across (s-4):
2s(s-4) = 2s(s) - 2s(4) =
2. (w+7)(w+3) �> again distribute the (w+7) across (w+3) [ Some use F.O.I.L. to remember: First, Inner, Outer, Last, but I just say to myself "everything in the first parenthesis must be multiplied by everything in the 2nd parenthesis. ] I'll give a few methods:
(i) F.O.I.L. : (w+7)(w+3) =
(ii) Distributive rule: (w+7)(w+3) =
(iii) Substitution using temporary variable:
Let K=w+7 �> (w+7)(w+3) =
3. (x+9)(x-2) =
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Hopefully this gives you enough to do the rest. Try them and message me if you have questions or want me to check your work.

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