SOLUTION: the length of a rectangle is (x+3)/x^2+x+12. the width is (x^2+7x+12)/w^2-9. what is the area in the 'simplest' form? Factored: (x+3)/x^2+x+12*(x+3)(x+4)/(x+3)(x+4) I get s

Question 1081083: the length of a rectangle is (x+3)/x^2+x+12. the width is (x^2+7x+12)/w^2-9. what is the area in the 'simplest' form?

Factored: (x+3)/x^2+x+12*(x+3)(x+4)/(x+3)(x+4)
I get stuck after this since I can't factor the first denominator.
Answer by josgarithmetic(39623) (Show Source): You can put this solution on YOUR website!
Parentheses placed where expected, and x instead of w (which probably was mistake):

length of a rectangle is .

the width is .

AREA, and then simplified:

-----you can finish multiplying in the denominator if you want.
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