SOLUTION: Solve the following fractional equation for all real roots - please provide answer step-by-step

SOLUTION: Solve the following fractional equation for all real roots - please provide answer step-by-step - thank you ! :) s+2/s^2-s-6 = 3-4/s-3

Question 1077251: Solve the following fractional equation for all real roots - please provide answer step-by-step - thank you ! :)
s+2/s^2-s-6 = 3-4/s-3

Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
can be written as
factoring a denominator.
For both sides of the equal sign to exist,
it must be and .
STEP 1 - Eliminate denominators:
If and ,
denominators can be eliminated by multiplying times
to get the equivalent equations

STEP 2 - Solve the resulting equation:
is a quadratic (degree 2) equation.
Quadratic equations always can be solved by either
"completing the square"
or using the quadratic formula.
Some quadratic equations can also be solved by factoring,
and if they can be solved by factoring,
and you are good at factoring,
it is the easiest way.
Factoring, you get
,
whose solutions are
<--->
and <--->
STEP 3 - Make sure to eliminate invalid solutions:
is not a valid solution,
because it causes denominator to be zero,
and the rational expression
to be undefined.
The only solution to the original equation is
.

NOTE:
If you meant ,
it should be written as (s+2)/(s^2-s-6) = 3-4/(s-3),
because when evaluating that expression for any value of s,
numerators and denominators must be calculated first, before dividing.
According to the order of operation conventions,
s+2/s^2-s-6 = .
Most calculators obey those conventions,
and if you do not enter the necessary parentheses,
you get the wrong answer.

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