Question 107717This question is from textbook
: Please help me with this problem. I know the common factor is 9, but I'm lost after that.
45q^4p^5+36qp^6+81q^2p^3
Thanks This question is from textbook
You can put this solution on YOUR website! 45q^4p^5+36qp^6+81q^2p^3
Look at the numbers: common factor of 9
Look at the powers of q: common factor of q^1
Look at the powers of p: commo factor of p^3
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Total common factor = 9qp^3
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Divide each term of the problem by 9qp^3 to get:
5q^3p^2 + 4p^3 + 9q
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Therefore the factored form of the original expression is:
= 9qp^3(5q^3p^2 + 4p^3 + 9q)
Cheers,
Stan H.
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