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If the zeroes of the quadratic polynomial x^2+(a+1)x+b are 2 and -3,then find the values of a and b
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Use the Vieta's theorem"
The sum of roots of a quadratic polynomial is equal to the coefficient at x with the opposite sign;
The product of the roots is equal to the constant term.
In your case it gives b = 2*(-3) = -6.
a+1 = -(2 + (-3)) = -(-1) = 1; hence, a = 0.
Answer. a = 0; b = -6.