SOLUTION: Could you please help me solve these equations: 2x^2-6x+7+7x^3-2x^2+4-3x I got:-9x+11+7x^3 The next one is:(5x^4+2x^3-4)-(2x^3+4x-7) I got:3+5x^4-4x The next one is:(x-2)(2x^2

Question 107303: Could you please help me solve these equations:
2x^2-6x+7+7x^3-2x^2+4-3x
I got:-9x+11+7x^3
The next one is:(5x^4+2x^3-4)-(2x^3+4x-7)
I got:3+5x^4-4x
The next one is:(x-2)(2x^2+x-7)
I got:2x^3-3x^2-9x+14
The last one is:12a^4+3a^2/3a^2
I got:4a^2 1 or would it be:+1 on the end?
I want to thank you in advance,you all are so nice for taking the time to help students like me.I never thought I would ever understand algebra,but since I found your site,and with all your help things are getting easier to understand.
Thanks again,jh
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given expression

Group like terms

Combine like terms

So you are correct

Start with the given expression

Distribute the negative

Group like terms

Combine like terms

So you are correct

Start with the given expression

Distribute

Group like terms

Combine like terms

So you are correct

Start with the given expression

Break up the fraction

Divide

Yes there would be a +1 on the end since there is a '+' in the expression and reduces to 1

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