The volume is V(x) = x*(4-2x)*(3-2x) = x*(4x^2 -2x*(4+3) + 12)) = x*(4x^2 - 14x + 12) = 4x^3 - 14x^2 + 12x. Take the derivative: V'(x) = 12x^2 - 28x + 12 Make it equal to zero: 12x^2 - 28x + 12 = 0, 3x^2 - 7x + 3 = 0,= = . = 1.768 (approximately), and it is clear that this root doesn't work. = 0.566 (approximately. Answer. The volume is maximal at x = 0.566 m.