SOLUTION: solve by factoring
a) x^3-2x^2-5x+6=0
b) 3x^3+2X^2-8x+3=0
solve 2x^4-x^3=7x^2-9x+3
Algebra.Com
Question 1068781: solve by factoring
a) x^3-2x^2-5x+6=0
b) 3x^3+2X^2-8x+3=0
solve 2x^4-x^3=7x^2-9x+3
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
1/1===-2===-5===6
=1====-1===-6===0
(x-1)(x^2-x-6)=0;(x-1)(x-3)(x+2)=0 roots are 1,3,-2
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1/3===2===-8===3
=3===5===-3===0
(x-1)(3x^2+5x-3)=0; roots are 1,(1/6)(-5+/- sqrt(61))
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