SOLUTION: Factor the following expression completely: {{{ 4a^2c^2-(a^2-b^2+c^2)^2 }}}
Since this is an odd number in the textbook, I have the answer. The answer is: {{{ (a+b+c)*(a+b-c)*(a
Question 1068250: Factor the following expression completely:
Since this is an odd number in the textbook, I have the answer. The answer is:
Even with the answer, I still do not know how to solve the problem.
First, I tried substitution. I made .
After substituting, the expression became:
I then expanded the binomial which got me the following expression:
I wasn't really sure what to do with , so I just re-expanded the problem replacing z with
After messy expansion and simplification, I got:
I thought this was a factor by grouping problem, so I separated the polynomial into three sections:
After factoring each of the three sections, I got:
I have no idea what to do next, and I am out of ammunition in solving this problem. Does anyone have any ideas in solving this? Answer by ikleyn(52797) (Show Source): You can put this solution on YOUR website! .
Factor the following expression completely:
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
= = (apply the formula = (x+y)*(x-y) )
= =
= =
= = ( apply again the same formula to EACH of the two factors )
= (b-a-c)*(b+a+c))*(b+a-c)*(b-a+c).
QED.