SOLUTION: Conner tosses a dog treat upward with an initial velocity of 13.7 meters per second. The height of the treat above the dog's 'h' in meters after 't' seconds is given by h=13.7t-4.9
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Question 1064527: Conner tosses a dog treat upward with an initial velocity of 13.7 meters per second. The height of the treat above the dog's 'h' in meters after 't' seconds is given by h=13.7t-4.9t^2.
If the dog doesn't jump, the dog catches the treat after about 2.8 seconds.
The maximum height the dog jumps is 9.6 meters.
How fast would Connor have to throw the dog treat in order to make it fly through the air for 6 seconds?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Conner tosses a dog treat upward with an initial velocity of 13.7 meters per second. The height of the treat above the dog's 'h' in meters after 't' seconds is given by h=13.7t-4.9t^2.
If the dog doesn't jump, the dog catches the treat after about 2.8 seconds.
Solve for "h"::
h = 13.7*2.8 - 4.9*2.8^2 is approximately zero
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The maximum height the dog jumps is 9.6 meters.
How fast would Connor have to throw the dog treat in order to make it fly through the air for 6 seconds?
Solve 9.6 = v*6 - 4.9*6^2
9.6 = 6v - 176.4
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6v = 186
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Ans: velocity = 31 ft/sec
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Cheers,
Stan H.
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