SOLUTION: Y=2/3x-3 in standard form? How do I solve this?
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Question 1061977: Y=2/3x-3 in standard form? How do I solve this?
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
y = (2/3)x - 3
3y = 2x - 9 ( multiplied both sides by 3)
-2x + 3y = -9 (subtracted 2x from both sides)
-2x + 3y + 9 = 0 (added 9 to both sides)
-2x + 3y + 9 = 0 is standard form of a straight line
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if you prefer the coefficient of x to be positive, you can multiply the above by -1:
2x - 3y - 9 = 0
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