SOLUTION: Use: f(x) = -2x^2 -5x +3 State the intervals over which f(x)

SOLUTION: Use: f(x) = -2x^2 -5x +3 State the intervals over which f(x) > 0

Question 1060525: Use: f(x) = -2x^2 -5x +3
State the intervals over which f(x) > 0
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!

f'(x) =
f''(x) =
Since f''(x) < 0, the function is (everywhere) concave down.
Setting f'(x) = 0:

This is a critical point, it is a maximum or minimum. In this case, since the function is concave down, it is a maximum.
So we know f(x) > 0 at the maximum, and it will be greater than zero for values between the zero crossings of f(x). To find the zero crossings, set f(x) = 0:

or
So on the interval

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