SOLUTION: Did I start out this problem correctly? Find the numerator:(-3x)/(5x-20)=(?)/(40-10x) I factored what I could and got this:(-3x)/[5(x-4)]=(?)/[-10(x-4)] I am not sure what

Algebra.Com
Question 1056647: Did I start out this problem correctly?
Find the numerator:(-3x)/(5x-20)=(?)/(40-10x)
I factored what I could and got this:(-3x)/[5(x-4)]=(?)/[-10(x-4)]
I am not sure what to do beyond this point.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
Trust what you learned about fractions, regardless if with variable expressions or plainly written real numbers.

, and you want to know v.






The negative factor,...










Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Did I start out this problem correctly?
Find the numerator:(-3x)/(5x-20)=(?)/(40-10x)
I factored what I could and got this:(-3x)/[5(x-4)]=(?)/[-10(x-4)]
I am not sure what to do beyond this point.
Where to go next!
Multiply the fraction: , by , to get: , and subsequently:
RELATED QUESTIONS

Dividing Rational equations The problem is x^2-3x-40(over/)5x divided by (x+5) I... (answered by jim_thompson5910)
i need this problem factored... (answered by rfer)
I did this problem and got it wrong could someone please help? Simplify:... (answered by uknouluvme89)
i need to simplify (3x)/(x^2-25)+(5x)/(x+5). i factored (x^2-25) to (x+5)(x-5). then i... (answered by lwsshak3)
If you could please let me know if I have this right, there is no example of this kind of (answered by venugopalramana,Earlsdon)
I did the following problem by synthetic division. Since this problem is rather... (answered by jim_thompson5910,CharlesG2)
If f(x)=5/x and g(x)=2/2x+1 , find the functions (a,b) and their domains. a.) (f o... (answered by jim_thompson5910)
So my question is how I would solve this proportion: 2x/4=5x+6/3 I also wanted to... (answered by Boreal)
I cant seem to factor this problem correctly. I am unable to see what I am doing wrong.... (answered by prabhjyot)