SOLUTION: 1.Use factoring and the zero product property to solve the question.
2x^3-6x^2-8x+24=0
2.Factor this expression over the complex numbers.
x^4+5x^2+4
Ex
Algebra.Com
Question 1056161: 1.Use factoring and the zero product property to solve the question.
2x^3-6x^2-8x+24=0
2.Factor this expression over the complex numbers.
x^4+5x^2+4
Express your answer as the product of binomials.
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1.Use factoring and the zero product property to solve the question.
2x^3-6x^2-8x+24=0
----
2x^2(x-3)-8(x-3) = 0
----
(x-3)(2)(x^2-4) = 0
----
2(x-2)(x+2)(x-3) = 0
-----------------------
x = 2 or x = -2 or x = 3
==================================
2.Factor this expression over the complex numbers.
x^4+5x^2+4
(x^2+4)(x^2+1) = 0
----
Express your answer as the product of binomials.
(x-2i)(x+2i)(x-i)(x+i) = 0
-----------------
Cheers,
Stan H.
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Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
1. x = 2 is a factor
use synthetic division:
(x-2)(2x^2 - 2x - 12) = 0
2(x-2)(x^2 - x - 6) = 0
2(x-2)(x+2)(x-3)) = 0
x is -2,2,3
2.Factor this expression over the complex numbers.
x^4+5x^2+4
(x^2 + 1)(x^2 + 4) = 0
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