SOLUTION: Find a polynomial function of degree 3 with the given numbers as zeros. 2,i, -i This is what I tried: F(x)=(x-2)(x+i)(x-i) I factored(x+i)(x-i) and got x^2-1 After that I fa

Question 1055344: Find a polynomial function of degree 3 with the given numbers as zeros.
2,i, -i
This is what I tried:
F(x)=(x-2)(x+i)(x-i)
I factored(x+i)(x-i) and got x^2-1
After that I factored (x^2-1)(x-2)
I got x^3-2x^2-x+2
I'm not exactly sure if I did that correctly.

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
There are three real roots in the graph

You want (x^2+1), because (x+i)(x-i)=x^2-i^2=x^2-(-1)=x^2+1
Now expand (x^2+1)(x-2)
x^3-2x^2+x-2

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