SOLUTION: What are the factors of a polynomial with the following zeroes: {{{ -1 }}}, {{{ 2/3 }}}, {{{ 2 }}}
A.) (x-1)(x+⅔)(x-2)
B.) (x-1)(3x-2)(x-2)
C.) (x+1)(x-⅔)(x+2)
D
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Question 1053751: What are the factors of a polynomial with the following zeroes: , ,
A.) (x-1)(x+⅔)(x-2)
B.) (x-1)(3x-2)(x-2)
C.) (x+1)(x-⅔)(x+2)
D.) (x+1)(3x-2)(x-2)
Thanks
Found 2 solutions by ewatrrr, Boreal:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
D. (x+1)(3x-2)(x-2)
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The values are the result of setting the factors equal to 0. They are opposite to the values given
so if (x+1)=0, a zero is -1.
x-(2/3)=0, or x=2/3 or 3x+2=0.
(x-2)=0
D is the answer. We don't use fractions in factorization, so while (x-(2/3)) is not mathematically wrong, (3x-2) is the factor.
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