SOLUTION: I am having a few issues if someone could help. The first problem is 3 with exponent of x+4 = 7 with exponent of 2x-1 Through all my notes I am finding nothing like this, my

Question 1042042: I am having a few issues if someone could help. The first problem is
3 with exponent of x+4 = 7 with exponent of 2x-1
Through all my notes I am finding nothing like this, my exmples are where I would take 3 as my base for 2nd equation
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3 with exponent of x+4 = 7 with exponent of 2x-1
----------------
3^(x+4) = 7^(2x-1)
---------
Since the variable is in the exponent, take the log::
(x+4)*log(3) = (2x-1)*log(7)
-------------------------------------
Now, get the x terms together::
x(log3-2*log(7)) = log(7)-4log(3)
x(-1.213) = -1.063
x = 0.877
-------------
Cheers,
Stan H.
--------------
RELATED QUESTIONS
I am having issues with e with exponent of 2x minus e exponent x minus 6... (answered by stanbon)

I am soon to be going back to college and its been awhile since I've had math to do. I... (answered by rapaljer)

I am having issues with a word problem. Hoping someone could help me please. A new... (answered by only4christ2)

Oh dear God please help me!!! We are studying Graphs of Exponential and Logarithmic... (answered by jim_thompson5910,scott8148)

I have the following problem. It has exponents so I will try to explain where they are. (answered by solver91311)

hi i really need help with these problems I would greatly appreciate it if you could... (answered by jorel1380)

I have tried every way i can think of to simplify this type of equation and have looked... (answered by suresh)

I am having some issues with logarithm equations and need some help. first problem: 2 (answered by lwsshak3)