SOLUTION: Hi. Could you tell me how I do this problem? (27a^3-8b^3)/(b^2-b-6)*(bc-b-3c+3)/(3ac-2bc-3a+2b)

SOLUTION: Hi. Could you tell me how I do this problem? (27a^3-8b^3)/(b^2-b-6)*(bc-b-3c+3)/(3ac-2bc-3a+2b)

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Question 1041309: Hi. Could you tell me how I do this problem?
(27a^3-8b^3)/(b^2-b-6)*(bc-b-3c+3)/(3ac-2bc-3a+2b)
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!

Factor all the numerators and denominators:

Cancel the (3a-2b)'s

Cancel the (b-3)'s

Cancel the (c-1)'s

All that left is:

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