SOLUTION: x^2+ax-bx-ab
Would it be
(x^2+ax)+(-bx-ab) = x(x+a)-b(x+a) = (x-b)(x+a)
Thank you
Algebra.Com
Question 1037583: x^2+ax-bx-ab
Would it be
(x^2+ax)+(-bx-ab) = x(x+a)-b(x+a) = (x-b)(x+a)
Thank you
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
That's what it is.
RELATED QUESTIONS
The following appears to prove that any two numbers are equal. Obviously it is wrong; can (answered by Edwin McCravy)
The following appears to prove that any two numbers are equal. Obviously it is wrong; can (answered by vleith)
factor:... (answered by scott8148)
The following appears to prove that any two numbers are equal. Obviously it is wrong; can (answered by stanbon,galactus,Theo)
Solve for x, {{{((a-x)/(a-b))-2=(c-x)/(b-c)}}}. Here's my working, if you could correct... (answered by god2012,nerdybill)
factor by grouping... (answered by Gogonati)
ax-a(a+b)=-x-(1+ab) (answered by Fombitz)
solve for x
ax+bx=c
solve for x
ax+bx = c
x(a+b) = c
x = c/(a+b)
(answered by chiexpert)
1.x+a/b + b=A
2.bx+a=dx+c... (answered by stanbon)