SOLUTION: Please help me to solve this - If a , b are the zeroes to f the polynomial p(x)=x^2-p(x+1)-c such that (a+1)(b+1)=0. What is the value of c

Question 1036258: Please help me to solve this - If a , b are the zeroes to f the polynomial p(x)=x^2-p(x+1)-c such that (a+1)(b+1)=0. What is the value of c
Found 2 solutions by robertb, ikleyn:
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
Let a,b be the zeroes of p(x).
==> -p = -(a+b) ==> p = a+b,
and
-p - c = ab.
Now (a+1)(b+1)= ab + a+b+1 =0 ==> -p-c + p + 1 = 0
==> c = 1, after simplifying.

Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
Please help me to solve this - If a , b are the zeroes to f the polynomial p(x)=x^2-p(x+1)-c such that (a+1)(b+1)=0. What is the value of c
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Hello, the author,

It is not a good style to keep the same letter for the polynomial p(x) and for one of its coefficients.

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