The system of equations is:
x + y = 15
xy = 15
Solve the first for y and substitute in the second:
y = 15-x
x(15-x) = 15
15x - x² = 15
15x - x² - 15 = 0
-x² + 15x - 15 = 0
x² - 15x + 15 = 0
And by symmetry, we may interchange x and y and get the
same result.
The irrational parts of x and y must have opposite signs
otherwise their sum could not be 15.
Answer:
So there are two numbers that such that their sum and product
are both 15.
Checking their sum:
Checking their product:
Edwin
You can put this solution on YOUR website! what 2 numbers multiply to give me 15 but add to give me 15
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a*b = 15
a+b = 15
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a = 15-b
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Substitute for "a" and solve for "b"::
(15-b)b = 15
-b^2 + 15b - 15 = 0
b^2 - 15b + 15 = 0
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b = [15 +- sqrt(225 - 4*15)]/2
b = [15 +- sqrt(165)]/2
b = (15/2)+(sqrt(165)/2), then a = (15/2 - (sqrt(165)/2)
OR
b = (15/2)-(sqrt(165)/2), then a = (15/2)+(sqrt(165)/2)
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Cheers,
Stan H.
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