SOLUTION: Solve the system of equations y = log_2 (2x) y = log_4 (x). Write your answers as ordered pairs (x,y). If you find more than one solution, list the solutions in order of incre

Question 1033368: Solve the system of equations
y = log_2 (2x)
y = log_4 (x).
Write your answers as ordered pairs (x,y). If you find more than one solution, list the solutions in order of increasing value of x and separate your answers with semi-colons. So, for example, you would type "(2,2);(4,6)" to say that x=2,y=2 and x=4,y=6 are the two solutions.
Answer by JoelSchwartz(130) (Show Source): You can put this solution on YOUR website!
y = log_2 (2x)
2^y=2x
(2^y)/2=2^(y-1)
2^(y-1)=x
y = log_4 (x)
4^y=x
2^2y=x
(2^2y)=4^y
2^2y=2^(y-1)
y-1=2y
y=-1
4^-1=1/4
(1/4,-1)

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