SOLUTION: In a sample of 300 students what is the probability of seeing 32% of the students choosing sports when it is known that on an average 25% of the students go for the sports. It is a
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Question 1030196: In a sample of 300 students what is the probability of seeing 32% of the students choosing sports when it is known that on an average 25% of the students go for the sports. It is assumed that selecting the sports is an independent event.
0.99
0
0.001 or 0.002
Not enough information is given
I have used Poisson distribution =POISSON.DIST(96,75,FALSE) which gave me 0.002. Is this correct?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
My scientific calculator is not powerful enough to evaluate , which is the true answer.
If you're going to use the Poisson to approximate this, with , you would get
, to four significant figures.
I tried approximating using the normal distribution using , and I got 0.9987-0.9953 = 0.0034, so more or else the real value should be in the close neighborhood.
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